Re: Using boost::function for publish-subscribe???

From: Andreas Huber (andreas_at_[hidden])
Date: 2001-11-21 17:36:23

Hi Peter

"Foreign" refers to a function object the class of which is not part 
of the boost library (and not an instantiation of a template provided 
by boost). As outlined in my previous post:

// MyFunctor is "foreign" ...
class MyFunctor
{
  public:
    void operator()();
};

int main()
{
  // ... f1 is not
  boost::function< void > f1 = MyFunctor();
}

I see that with the design of boost::function ANY function object is 
as good as another. However, that would not be possible if 
boost::function provided equality operations. Please see my reply to 
Doug.

Thanks,

Andreas