From: Peter Dimov (pdimov_at_[hidden])
Date: 2002-06-04 13:33:29
From: "Dirk Gerrits" <dirkg_at_[hidden]>
> From: "Peter Dimov" <pdimov_at_[hidden]>
> > From: "David Abrahams" <david.abrahams_at_[hidden]>
> > > From: "Peter Dimov" <pdimov_at_[hidden]>
> > >
> > > I know that. I just wanted the same kind of "extra" facility you could
> > > request for __stdcall. In other words, for the platforms where it's
> > needed,
> > > #include <boost/bind/extern_c.hpp>.
> > There is no way to supply the overload. extern "C" is not allowed on
> > parameter declarations AFAIK; the "qsort" way is to use an intermediate
> > typedef
> I have no idea what intermediate typedef trickery you are referring to, so
> forgive me if I say something stupid.
Apologies for the highly compressed writing style.
What I meant was that you can declare a pointer to an extern "C" function
using a typedef:
typedef void (*pf) ();
and then use this pointer as an argument:
void g(pf f); // 'g' is not extern "C" itself
but you can't do
void g(extern "C" void (*f) ());
Since bind uses overloads of the form
template<class R> ... bind(R (*f) ());
the typedef trick doesn't work.
> > but we don't have typedef templates, alas.
> There's a workaround which mimics typedef templates. Can't this be used
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