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From: Carlo Wood (carlo_at_[hidden])
Date: 2002-08-30 10:56:30
On Fri, Aug 30, 2002 at 11:42:37AM -0400, Rob Stewart wrote:
> That presumes the caller wants to create a string to pass to the
> function, of course. That same thing can be done like this:
>
> std::string out = "You are inside ";
> out += demangle(mangled_function_name);
But that would add an additional copy
of the demangled name.
-- Carlo Wood <carlo_at_[hidden]>
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