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From: David Abrahams (dave_at_[hidden])
Date: 2002-09-04 14:50:50

From: "Thomas Wenisch" <twenisch_at_[hidden]>

> This is incorrect. The code returns a *const* reference to the
> temporary. This extends the life of the temporary to the life of the
> reference.

Yes, but that reference is created within the function. There's another
reference on the outside of the function. By your logic, the temporary
would live forever in this code:

int f();
struct hold { hold(int const& x_) : x(x_) {} int const& x; }
hold* h = new hold(f());

But it doesn't work that way.

           David Abrahams * Boost Consulting
dave_at_[hidden] *

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