[boost] Re: How to convert a template parameter into a string

From: Dirk Gerrits (dirk_at_[hidden])
Date: 2003-02-28 16:00:49

Robert Allan Schwartz wrote:
> The attached document was submitted for publication to C/C++ Users Journal
> today, but I thought it might be worth submitting to Boost as well.
> 
> Perhaps my spelling class template could be folded into type_traits?

[code snipped]

Looks interesting, but I'm not sure if it's such a huge advantage over:

template <typename T>
void foo(T)
{
     cout << "T is " << typeid(T).name() << endl;
}

The resulting string of your method is more portable of course, but is 
that the only reason?

Regards,
Dirk Gerrits