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From: John Torjo (john_at_[hidden])
Date: 2003-04-24 07:20:58

> void f( in_out< int > is_not_changed_ )
> {
> // use is_not_changed_, but don't change it
> }

I think there would be a much bigger problem (code inside the function would

Just consider

void add_char( std::string & str, char ch)
{ str += ch; }

Now, if we change it so be in_out, we'll have to use a .ref()-like function.

void add_char( in_out<std::string> str, char ch)
{ str.ref() += ch; }

Of course, this is a simple example, but it illustrates the point.
The code would become obfuscated.

Frankly, I donot like it.


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