|
|
Boost : |
From: Thomas Witt (witt_at_[hidden])
Date: 2003-06-05 03:04:07
Daryle,
On Thursday 05 June 2003 01:28, Daryle Walker wrote:
>
> Actually, that reason isn't accurate. The '\n' is an expression of
> type char, and all output streams can print a char object with operator
> <<, even if the stream's character type isn't char. (The stream will
> secretly call the widen member function.)
Yep, you are right. This will tell me to stop talking about io issues from
memory ;-).
Thomas
-- Dipl.-Ing. Thomas Witt Institut fuer Verkehrswesen, Eisenbahnbau und -betrieb, Universitaet Hannover voice: +49(0) 511 762 - 4273, fax: +49(0) 511 762-3001 http://www.ive.uni-hannover.de
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk