RE: [boost] Spirit Question

From: Paul Hamilton (paul_at_[hidden])
Date: 2003-08-21 20:24:49

hartmutkaiser_at_[hidden] (Hartmut Kaiser) wrote:

> The first *anychar_p eats up all your input (it matches zero or more
> occurences of any char :-). There are several ways to circumvent this
> problem:
>     list_wo_item = (*(anychar_p - ','))[append (vec_list)]
>>> *( ',' >> (*(anychar_p - ','))[append (vec_list)] )
>         ;

Thanks for that.

My complete expression (which works great!) is:

     list_wo_item = '[' >>
                        (*(anychar_p - (ch_p(',') | ch_p(']'))))[append(vec_list)] >>
                                *(',' >> (*(anychar_p - (ch_p(',') | 
ch_p(']'))))[append(vec_list)]) >>
                        ']';

Which matches my "[x,y,z]" string perfectly.

Yours was the push that I needed to be able to work this stuff out.

>     list_wo_item = list_p((*anychar_p)[append(vec_list)], ',');

I couldn't get this to do anything. How would it work in the more 
complicated example above. Looking through the code, I couldn't really 
understand what t actually does.

>     parse_info<> result = parse (plist_wo_item, list_wo_item, space_p);

This gives me a compile error. If you look at the "parse" template, the 
only version that seems to take the "space_p" parser is the one 
accepting iterators, and since my actual argument is a std:;string, I 
tried:

parse_info<> result = parse (str.begin(), str.end(), list_wo_item, 
space_p);

Which also doesn't compile.

Paul.

---------------------
Paul Hamilton
pHamtec P/L - Software Makers
http://www.phamtec.com/
mailto:paul_at_[hidden]

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