From: Jan Van Dijk (janvandijkinjapan_at_[hidden])
Date: 2003-10-17 07:29:17
On Thursday 16 October 2003 21:38, Jeff Flinn wrote:
> "Jan Van Dijk" <janvandijkinjapan_at_[hidden]> wrote in message
> > Unfortunately the algebra (the transformation properties) is not linear.
> > consider conversion from the temperature-'base vector' K (kelvin) to C
> > (Celsius), C=K-273.15.
> Looks perfectly linear to me? y = mx + b => C = (1)K - 273.15
In linear algebra (the context of Deane's) mail the word 'linear' has a
diferent meaning. An operator L is linear in its argument iff
For starters this implies that L(0)=0 (just take a=b=0). Obviously this is not
true for the operator L(T)=T-273.15, the transformation from K to C.
-- Keio-Tsuushin Residence Jan van Dijk, Room 210 2 Chome 19-30, Mita Minato-ku 108 Tokyo, Japan jan_at_[hidden] tel: +81 3 5476 9461 (home)
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