[boost] Re: Constants framework (long)

From: Thorsten Ottosen (nesotto_at_[hidden])
Date: 2003-10-17 19:37:20

[snip]
>   The framework itself allows compilers to produce code which is as
>   good as hand-written code. Of course, not all compilers make use of
>   these opportunities. I tested the GCC and the Intel compiler, the
>   latter can produce optimal code, the former has some problems,
>   though. Last tested: GCC 3.3, maybe this has improved since, further
>   testing is definitly needed. To be fair, I should also mention that
>   Paul Bristow tried the run the code through the VC++, which
>   failed. The code seems to be a bit challanging, but I haven't given
>   up hope. If you can make it work for the VC++, please let me know :)

I could compile some of it with vc7:

int main()
{
    // Usage example:

    using namespace boost::math;
    using std::sqrt;
    using boost::math::sqrt;

    const float f = 1.F;
    const double d = 1.;
    const long double ld = 1.L;

    cout << pi * f * f << endl;
    cout << pi * d * d << endl;
    cout << pi * ld * ld << endl;
/*
    cout << static_cast< double >( pi ) << endl;
    cout << static_cast< float >( pi ) * d * d << endl;
*/
    cout << pi * pi * f << endl;
    cout << pi * pi * d << endl;
    cout << pi * pi * ld << endl;

    cout << pi + pi - pi * pi / pi + d << endl;
/*
    cout << pi * pi * pi * f << endl;
    cout << pi * pi * pi * d << endl;
    cout << pi * pi * pi * ld << endl;

    cout << pi + 2. << endl;
    cout << 2. + pi << endl;

    cout << sqrt( two ) * sqrt( 2.F ) << endl;
    cout << sqrt( two ) * sqrt( 2.L ) << endl;

    cout << sqrt( sqrt( two + pi ) ) + d << endl;

    // double dx = sqrt( pi );
    // cout << ( sqrt( pi ) ) << endl;
    */
}

For the rest, I havn't looked more into it.

cheers

Thorsten