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From: Daryle Walker (darylew_at_[hidden])
Date: 2004-01-26 15:12:13

On 1/24/04 8:31 PM, "Howard Hinnant" <hinnant_at_[hidden]> wrote:

> On Jan 24, 2004, at 7:20 PM, Daryle Walker wrote:
>> Can you have both? The built-in signed integral types would go to the
>> "ptrdiff_t" version and the built-in unsigned integral types would go to the
>> "size_t" version. Or do the conversion rules produce an ambiguity error
>> instead?
> If you simply define both, you're setting yourself up for an ambiguity error.
> For example if:
> ptrdiff_t == long
> size_t == unsigned long
> then an int argument might be able to convert to either with equal ease.

I know that an "int" value could fit in an "unsigned long" at run-time. But
at compile-time, are the two conversions considered equal, or will the
compiler always prefer the "long" version?

Daryle Walker
Mac, Internet, and Video Game Junkie
darylew AT hotmail DOT com

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