|
Boost : |
From: Neal D. Becker (nbecker_at_[hidden])
Date: 2004-02-03 09:26:21
I ran into the following problem. I have an algorithm which looks like:
template<typename in_t, typename out_t>
void Alg (in_t in, in_t inend, out_t out) {
for (; in != inend; in++, out++)
do_something()
}
Now if I want to call this algorithm more than once, it would be convenient
to pass out by ref, so it would be incremented:
Alg (v.begin(), v.end(), boost::ref (out))
that is, pass a reference to some kind of output iterator
this fails, because boost::ref doesn't have operator++ defined for
reference_wrapper.
My question is, should boost::ref forward operators like ++ so that this
would work?
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk