[boost] Re: FC++: lambda

From: Matthew Vogt (mvogt_at_[hidden])
Date: 2004-02-18 02:07:43

Brian McNamara <lorgon <at> cc.gatech.edu> writes:

> Well, technically you don't even need lambda to implement monads.  But
> to do monads well/easily, you need syntax sugar (along the lines of
> Haskell's "do" notation or FC++'s comprehensions).  This sugar requires
> explicit lambda variables (the same kind you see in FC++ lambda's
> let/letrec).  It's unclear to me if/how to do that with (or extend)
> boost::lambda in a natural way to get this.
> 

So, the less-concise syntax of fcpp::lambda means that there's more often
a term in an expression which can be used to cause an operator overload to 
be selected from the lambda library?

> This is a pretty rambling and vague-sounding answer, I suppose, hrm.
> 

Depends on whether you agree with my attempt to re-express it, I guess :)