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From: Brian McNamara (lorgon_at_[hidden])
Date: 2004-05-03 11:02:25
On Mon, May 03, 2004 at 09:42:16AM -0400, Arkadiy Vertleyb wrote:
> > Shortcut for:
> >
> > BOOST_TYPEOF(_1 > 15 && _2 < 20) fun(_1 > 15 && _2 < 20);
>
> On the other hand, since a lambda expression returns a default-constructed
> functor (does it? -- I am unable to verify it right now) the above doesn't
> make a lot of sence for Lambda... One can just write:
>
> BOOST_TYPEOF(_1 > 15 && _2 < 20) fun;
I don't think so. I am pretty sure that
_1 < 3.3
and
_1 < 4.4
have the same _type_ (but they have different "double" _values_ encoded
in the run-time structure when constructed).
-- -Brian McNamara (lorgon_at_[hidden])
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