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From: Jaakko Jarvi (jajarvi_at_[hidden])
Date: 2004-05-13 15:37:10

On May 13, 2004, at 3:32 PM, Neal D. Becker wrote:

> Any reason lambda functions can't meet requirements for
> std::unary_function,
> for example? Specifically, it seems result_type is not defined.
> For example boost::constant(0) doesn't have result_type, so can't be
> used
> where a std::unary_function is needed.

In general the result_type is not known until the parameter types of
the lambda_functor
are known. So for consistency (or laziness), result_type is not
provided for any
lambda functor.


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