From: Jaakko Jarvi (jajarvi_at_[hidden])
Date: 2004-05-13 15:37:10
On May 13, 2004, at 3:32 PM, Neal D. Becker wrote:
> Any reason lambda functions can't meet requirements for
> for example? Specifically, it seems result_type is not defined.
> For example boost::constant(0) doesn't have result_type, so can't be
> where a std::unary_function is needed.
In general the result_type is not known until the parameter types of
are known. So for consistency (or laziness), result_type is not
provided for any
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk