[boost] Re: [type_traits] fully qualified names

From: Jody Hagins (jody-boost-011304_at_[hidden])
Date: 2005-03-10 16:44:23

I hate replying to my own post, but I forgot to add...

Yes, I know that I am using a type, not an integral constant value, and
I should have come up with an example in that vein.  However, all the
examples and docs use the fully qualified version for both types and
values...