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From: David Abrahams (dave_at_[hidden])
Date: 2005-06-27 15:11:11
"Robert Ramey" <ramey_at_[hidden]> writes:
> 1) as written above, it fails to compile on a conforming compler. This is
> because the << operator takes a reference as its argument.
Why is it a good idea for << to take its 2nd argument by non-const
reference??
-- Dave Abrahams Boost Consulting www.boost-consulting.com
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