Re: [boost] [function_types][docs] Preview: Overview, Introduction, Tag types

From: Rob Stewart (stewart_at_[hidden])
Date: 2005-07-09 15:25:18

From: Tobias Schwinger <tschwinger_at_[hidden]>
> Rob Stewart wrote:
> > From: Tobias Schwinger <tschwinger_at_[hidden]>
> > 
> >>Default values are selected for properties not specified by the 
> >>tag. The next example creates the type of a function (variadic in 
> >>this case) of the default calling convention. int(int...).
> > 
> > Something got munged here.  Here's another try:
> > 
> >    The following expression produces a function type for variadic
> >    functions with a first parameter of type int which return an
> >    int.  Since a calling convention isn't specified, the default
> >    calling convention is used.
> 
> OK. But why add so much talk about the component types here?
> 
>      The following expression produces a function type for variadic function.
>      Since a calling convention isn't specified, the default calling convention
>      is used.
> 
>        function_type<mpl::vector<void,int>, variadic>::type // is void (int...)
> 
> Should be enough, right?

Yes, that's fine.

-- 
Rob Stewart                           stewart_at_[hidden]
Software Engineer                     http://www.sig.com
Susquehanna International Group, LLP  using std::disclaimer;