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From: David Abrahams (dave_at_[hidden])
Date: 2005-07-22 10:33:11
Rob Stewart <stewart_at_[hidden]> writes:
> From: David Abrahams <dave_at_[hidden]>
>> Rob Stewart <stewart_at_[hidden]> writes:
>> > From: David Abrahams <dave_at_[hidden]>
>> >
>> > On the other hand\x{2014}as you may recall from the parameter
>> > table\x{2014}``color_map`` is an \x{201C}out\x{201D}
>> > parameter, so it really should be passed by non-const
>> > reference.
>> >
>> > Note that "color_map" and "out" are quoted significantly
>> > differently with no apparent reason.
>>
>> No, ``color_map`` isn't quotation; it's markup for "code font." Look
>> at the HTML.
>
> I was looking at it in the browser. I saw "``color_map``" and
> "<fancy open quote>out<fancy close quote>" so I saw no "code
> font" markup. Unless I'm misunderstanding you, something is
> wrong.
Thanks, I just fixed it.
>> > A keyword object has a pair of operator= overloads that ensure
>> > we can pass anything by name, but when an \x{201C}out\x{201D}
>> > parameter is passed positionally, that's no help: in this
>> > case, core::depth_first_search would end up with a const
>> > reference to the color_map and compilation will fail when
>> > mutating operations are used on it.
>> >
>> > That's a long sentence and did you really mean to say "we can
>> > pass *anything*" (emphasis mine)?
>>
>> Yep.
>
> I didn't look, but it sounded odd that one could pass an int,
> char *, std::complex, etc.
Well, you can at least pass anything to the keyword's operator=.
Whether or not the depth_first_search function compiles is another
matter.
>> > Perhaps this would be better:
>> >
>> > A keyword object has a pair of operator = overloads that
>> > ensure we can pass references to const or non-const objects by
>> > name,
>>
>> You don't get to pass references to anything in C++. You pass the
>> object referred to by a name or expression and the callee decides
>> whether it goes by reference.
>
> Yeah, I misspoke (miswrote?). I was referring to the parameter
> type when I should have been discussing the allowable argument
> types.
>
>> Also, the point is that you can pass both lvalues and rvalues, or
>> temporaries and non-temporaries, not that the objects can be const or
>> non-const. You can do that just fine with a single templated function
>> taking a T& (T will be deduced as U const when the object is constant).
>
> Pedantry aside, that's not the same as *anything*.
Pedantry aside, what else is there?
>> > but when an "out" parameter is passed positionally,
>> > that's no help. In that case, core:;depth_first_search would
>> > end up with a...."
>
> What about splitting the sentence into two?
How's this?
A keyword object has a pair of ``operator=`` overloads that ensure
we can pass anythingâtemporary or not, ``const`` or notâby name,
while preserving the mutability of non-temporaries:
.. parsed-literal::
template <class A> // handles non-const,
|ArgumentPack| operator=(A&); // non-temporary objects
template <class A> // handles const objects
|ArgumentPack| operator=(A const&); // and temporaries
However, when an âoutâ parameter is passed positionally, there's no
keyword object involved. With our ``depth_first_search`` overload
set above, the ``color_map`` will be passed by ``const`` reference,
and compilation will fail when mutating operations are used on it.
The simple solution is to add another overload that takes a
non-``const`` reference in the position of the âoutâ parameter:
-- Dave Abrahams Boost Consulting www.boost-consulting.com
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