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From: David Abrahams (dave_at_[hidden])
Date: 2005-12-03 16:22:35
"Eric Niebler" <eric_at_[hidden]> writes:
> David Abrahams wrote:
>> Eric Niebler <eric_at_[hidden]> writes:
>>
>>>
>>>Put the overload in an associated namespace of the type. Or for maximum
>>>portability, you could put the overload at global scope.
>>
>>
>> Really? If invoked from within a template, global scope overloads
>> won't be found unless an argument is in the global namespace or the
>> overloads happen to appear before the point of definition of the
>> template.
>
>
> That was the idea, yes.
>
>
>> If you want a way to make this portable, consider adding a dummy
>> parameter that comes from namespace Boost and asking people to
>> overload there (the Ramey trick).
>
>
> I'm not sure how this helps on compilers that don't do ADL. This is
> a macro. BOOST_FOREACH(foo, bar) will expand to something that makes
> a non-qualified call to boost_foreach_has_cheap_copy *in the context
> of the BOOST_FOREACH invocation*. This could be any context, in any
> namespace.
Right. Including from within a template, which could foil lookup in
the global namespace.
> If I want this to work on compilers that don't do ADL,
> requiring people to make their overloads visible at global scope
> seems necessary, but I've likely overlooked something.
namespace boost
{
template <class T>
struct foreach_has_cheap_copy
{
char (& test(...)) [2];
char test(mpl::true_*);
typedef mpl::bool_<
sizeof(
test(
boost_foreach_has_cheap_copy(
(T*)0,
boost::whatever()) ))
> type;
};
}
Now all compilers will look in namespace boost, whether or not they
support ADL.
-- Dave Abrahams Boost Consulting www.boost-consulting.com
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