Re: [boost] [shared_ptr] constructor accepting auto_ptr

From: Yuval Ronen (ronen_yuval_at_[hidden])
Date: 2005-12-07 11:20:13

Peter Dimov wrote:
> The reference adds a strong exception safety guarantee. If the shared_ptr 
> constructor fails, the source auto_ptr is left intact. Pass by value would 
> have already zeroed out the source.
> 
> If you want to achieve the equivalent of pass by value, you can use an 
> explicit .release().
> 
> This warning would actually be an error on a stricter compiler.
> 
> One happy day the compiler writers will bring us the rvalue reference, the 
> constructor will take auto_ptr &&, and all will be well with the world. :-) 

Does that mean that on a stricter compiler, when passing a temporary 
auto_ptr, I *have* to use the '.release()' way, and *can't* get the 
strong exception guarantee?

Thanks a lot to both of you Peter and Howard for your help.