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From: Eric Niebler (eric_at_[hidden])
Date: 2005-12-20 18:52:11


Gabriel Dos Reis wrote:
> "Eric Niebler" <eric_at_[hidden]> writes:
>
> | Now look above it: "typedef foo const cfoo". So the type of the 3rd
> | operand is "rvalue of foo const". The 2nd operand gets converted to
> ^^^^^^^^^
>
> [there is no type "rvalue of ..." as you said earlier]
>

Thanks for the correction. So, the above would be more properly stated,
"the 3rd operand is an rvalue of type foo const," is that right?

-- 
Eric Niebler
Boost Consulting
www.boost-consulting.com

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