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From: Eric Niebler (eric_at_[hidden])
Date: 2005-12-20 18:52:11

Gabriel Dos Reis wrote:
> "Eric Niebler" <eric_at_[hidden]> writes:
> | Now look above it: "typedef foo const cfoo". So the type of the 3rd
> | operand is "rvalue of foo const". The 2nd operand gets converted to
> ^^^^^^^^^
> [there is no type "rvalue of ..." as you said earlier]

Thanks for the correction. So, the above would be more properly stated,
"the 3rd operand is an rvalue of type foo const," is that right?

Eric Niebler
Boost Consulting

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