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From: Fernando Cacciola (fernando_cacciola_at_[hidden])
Date: 2006-03-29 14:40:27

David Abrahams wrote:
> David Abrahams <dave_at_[hidden]> writes:
>> Ulrich Eckhardt <doomster_at_[hidden]> writes:
>>> On Wednesday 29 March 2006 08:05, Václav Veselý wrote:
>>>> I'm confused with syntax. new_<T> always creates auto_ptr<T>. How
>>>> can I create for example shared_ptr<T>?
>>> You probably can't, but:
>>> - std::auto_ptr is much less resource intensive (shared_ptr
>>> requires an additionally, dynamically-allocated structure to hold
>>> some internals) - you don't need to, as auto_ptr converts to
>>> shared_ptr, there is a special ctor taking an auto_ptr
>> Unfortunately for this particular facility, the converting
>> constructor
>> is explicit, so you can't do
>> f(new_<T>(a, b, c))
>> if f takes a shared_ptr<T>.
Then isn't it worth generalizing new_<> to all sorts of smart pointer and


 f( new_< any_smart_ptr<T> >(a, b, c)) ;

As long as there's a way to get the 'element_type' from 'any_smart_ptr'
it'll work.

On top of that there could be the friendlier: make_auto_ptr,
make_shared_ptr, etc...

Fernando Cacciola

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