Re: [boost] Infinite precision integer draft

From: Hervé Brönnimann (hbr_at_[hidden])
Date: 2006-05-26 10:57:34

> The counting starts with bit number 0.
> So is_odd now becomes lowest_bit() == 0.

But isn't lowest_bit() != 0 an overkill for checking that a number is  
even? (I mean, first computing the order of the lowest_bit, then  
comparing to 0...)  I think there is room for lowest_bit /  
highest_bit as well as for is_odd and is_even.  Perhaps it will be  
more readable than the idiom "integer(x) %2 == 0".
--
Hervé Brönnimann
CIS, Polytechnic University
hbr_at_[hidden]