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From: me22 (me22.ca_at_[hidden])
Date: 2006-06-09 12:34:18

On 6/9/06, Yuval Ronen <ronen_yuval_at_[hidden]> wrote:
> Are you implementing the big_endian<T> class as holding a member of type
> T? If you do (that's the most logical way, I think), then it sounds most
> strange to me. Is it just one compiler that's causing problems? Have you
> tried on more than one compiler?
Yes, it's holding it as a member.

I've tried it (with the same results) in g++ 3.3.6, 3.4.6, and 4.1.1.
I just installed icc to try it with that, but I think there's a
library mismatch or something with the rest of my system as I can't
even get hello world to compile with it.

I think it might just be a matter of the compiler getting lost in all
the templates and being careful. When I try a simple test case with
basically the same hierarchy and members it works fine:

template <typename T, typename U>
struct operators2 {};

template <typename T, typename U>
struct int_wrapper_operators2 {};

template <size_t n_bits>
struct exact
 : int_wrapper_operators2< exact<n_bits>, int > {
    char a[n_bits/8];

template <typename T>
struct big_endian
 : int_wrapper_operators2< big_endian<T>, int > {
    T val;

Resulting in
( sizeof( operators2<float,int> ) ) = 1
( sizeof( int_wrapper_operators2<float,int> ) ) = 1
( sizeof( long ) ) = 4
( sizeof( big_endian<long> ) ) = 4
( sizeof( exact<24> ) ) = 3
( sizeof( big_endian< exact<24> > ) ) = 3

Is there possible a class deep down in operators<T,U> that is only
templated on U? If there is, maybe the compile doesn't want to put
the instance from integer_cover_operators< exact<24>, int > and
integer_cover_operators< big_endian<exact<24> >, int > at the same

I've also attached the problematic code as well, in the hopes that
someone can find the problem or see whether it's gcc-specific. ( The
integer_cover_operators.hpp is the same as Beman's, with the exception
of using boost::operators<T,IntegerType> instead of
boost::operators<T>. This solved an issue where std::numeric_limits<
boost::exact<24> >::min()-1 was ambiguous. )

~ Scott McMurray

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