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From: Geoffrey Irving (irving_at_[hidden])
Date: 20060619 13:43:43
On Tue, Jun 20, 2006 at 12:23:37AM +0700, Oleg Abrosimov wrote:
> Gerhard Wesp wrote:
> > On Mon, Jun 19, 2006 at 10:04:21AM +0200, Matthias Troyer wrote:
> >> As a physicist I am completely baffled and confused. What do you mean
> >> by rank of a quantity? Do you mean the size of a vector/matrix? If
> >
> > I understood Olegs post about rank such that it was something that would
> > allow to distinguish energy from torque, e.g. Is there such a thing?
> > Off the top of my head, I cannot think of a situation where you might
> > want to add energy to torque, even if in the SI system they have the
> > same dimension (Nm).
> >
> > Same thing for angular velocity [rad/s] and frequency (1/s). You
> > probably don't want to add both, even if in SI they're both in s^1. Is
> > this maybe a deficiency of SI? Would it make sense to add the unit
> > "radians" that is used colloquially anyway, to the system?
>
> You are almost right, but in the end you've chosen a wrong direction.
>
> There is a very good article in wikipedia about tensors in which tensor
> rank is also described:
> http://en.wikipedia.org/wiki/Tensor
<snip>
> This problem can not be solved only inside dimensional analysis. I hope
> that it is clear from this post.
> The solution is to take into account the rank of quantity (rank is 0 >
> scalar; rank is 1 > vector, ...)
Having rank also solves the following problem I was wondering about: how
do you define vector scalar multiplication in a sufficiently restrictive
way. Without a notion of rank, matrix * vector could be ambiguous with
scalar * vector since (matrix * x, matrix * y, matrix * z) would be a valid
vector<matrix<T> >.
Geoffrey
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