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From: Dean Michael Berris (mikhailberis_at_[hidden])
Date: 2006-07-07 16:55:57
On 7/6/06, Emil Dotchevski <emildotchevski_at_[hidden]> wrote:
>
> template <class T>
> exception_info * get_exception_info( T & );
>
> It can be used in a catch( T & ) block, to check if the exception object has
> a sub-object of class exception_info.
>
Why return a pointer? How about considering the use of a reference
instead? Perhaps:
template < typename T >
exception_info & get_exception_info ( T & );
That way, the return can only be accessed using an exception_info
reference. Consider this example (which is considerably cleaner to
read, IMO) :
try {
throw failed<read_error>() << wrap_string<tag_file_name>("example.txt");
} catch (read_error & e) {
exception_info info = get_exception_info(e);
if (info) {
// deal with the info...
}
// deal with the exception...
};
This also avoids the possibility of mis-use of pointers, because
client code can still do a cast of the pointer to refer to something
else -- which although it is hackish, is something you'd want to
avoid. It also makes the following possible:
std::cout << get_string<tag_file_name>(get_exception_info(e)) << std::endl;
Which is a little long for my taste, but readable nonetheless.
HTH
-- Dean Michael C. Berris C/C++ Software Architect Orange and Bronze Software Labs http://3w-agility.blogspot.com/ http://cplusplus-soup.blogspot.com/ Mobile: +639287291459 Email: dean [at] orangeandbronze [dot] com
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