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From: me22 (me22.ca_at_[hidden])
Date: 2006-07-10 20:06:35

On 7/10/06, Sohail Somani <s.somani_at_[hidden]> wrote:
> Isn't shared_ptr<T> is supposed to be like T* which has ordering? In
> this case, it's a non-issue no?
My understanding is that < is only well-defined for pointers into the
same array and that < between to arbitrary pointers is otherwise some
sort of UB.

It's less<T*> that provides a full ordering for arbitrary T*s. (By
specialising std::less.)

~ Scott McMurray

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