Re: [boost] Please don't define a fake "operator <" justfor ordered containers

From: Sohail Somani (s.somani_at_[hidden])
Date: 2006-07-18 19:07:21

> No.  For pointers going into the same array segment 
> (including one-past-end)
> or the same access-level class block, operator "<" is 
> defined.  Using the
> operator is unspecified if the pointers are from different spans.  The
> "std::less<T*>" specializations have to give the same results as the
> operator when the operator is defined, but must give a total 
> ordering so
> pointers from different spans (or NULL) can be compared.  Due 
> to potential
> exclusivities in comparison domains, it's possible that the 
> operator and the
> class template use separate definitions.

I must leave it in your capable hands to provide a summary and solution
for this thread. It would be very interesting.