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From: Rodolfo Lima (rodolfo_at_[hidden])
Date: 2006-11-29 16:43:35
Lambda's return type deduction for a pointer to member action doesn't honour
the object constness.
Regardless of the object constness, the return type is always a non const
reference to the member type.
The following code illustrates the issue:
struct aux
{
aux() : b(1) {}
int b;
};
struct aux_ptr
{
aux_ptr(aux *ptr=NULL) : m_ptr(ptr) {}
~aux_ptr() { delete m_ptr; }
template <class R> R &operator->*(R aux::*m) { return m_ptr->*m; }
template <class R> const R &operator->*(R aux::*m) const { return
m_ptr->*m; }
private:
aux *m_ptr;
};
int main()
{
// This compiles nicely
aux_ptr ptr(new aux());
cout << (_1->*&aux::b)(ptr) << endl;
// This fails to compile.
const aux_ptr cptr(new aux());
cout << (_1->*&aux::b)(cptr) << endl;
return 0;
}
The second part should compile if other_action<member_pointer_action>
honoured _1's constness.
Thanks,
Rodolfo Lima
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