Re: [boost] [lambda] Wrong return type for dereference for pointerto member

From: Rodolfo Lima (rodolfo_at_[hidden])
Date: 2006-11-30 07:39:35

>>     // This compiles nicely
>>     aux_ptr ptr(new aux());
>>     cout << (_1->*&aux::b)(ptr) << endl;
>>
> Hmm... why does this even compile? strange.

I see, after looking at the code I don't see a specialization for 
plain_return_type_2<other_action<member_pointer_action> >. FYI I'm using g++ 
4.1.1.

>> Both versions above are delayed calls to user-defined operator->* and
> the in general the library
> won't guess what the result type should be.
> In the latter case the lib would have to guess that constness of
> aux_ptr means
> that R should be constified in the return, which is too much guess work.

Maybe lambda could support what I think is a common scenario, i.e., smart 
pointer-like objects. The worst think that may happen is, IMO, a compilation 
failure.

Regards,
Rodolfo Lima.