Re: [boost] [thread] condition::notify with unlocked mutex

From: Peter Dimov (pdimov_at_[hidden])
Date: 2006-12-11 16:44:21

Sebastian Redl wrote:
> Anthony Williams wrote:
>> I believe the following is a valid scenario:
>> 
>> Thread A:
>> 
>> WaitForSingleObject(hSemaphore) // blocks
>> 
>> Thread B:
>> 
>> ReleaseSemaphore(hSemaphore,1)
>> 
>> Thread C:
>> 
>> WaitForSingleObject(hSemaphore) // returns immediately
>> 
>> Thread A still blocked
>> 
>> I can't remember where I got this impression, and I may be wrong.
>> 
> No, you're absolutely right. This is something that, for example, The
> Old New Thing had an article about.

Yep, here it is:

http://blogs.msdn.com/oldnewthing/archive/2006/03/13/550402.aspx