Re: [boost] [optional] optional<T &> and the arrow operator

From: Jeffrey Yasskin (jyasskin_at_[hidden])
Date: 2007-02-12 20:02:42

On 2/9/07, Felipe Magno de Almeida <felipe.m.almeida_at_[hidden]> wrote:
> On 2/9/07, Mathias Gaunard <mathias.gaunard_at_[hidden]> wrote:
> > Felipe Magno de Almeida wrote:
> > > Why would it? T* and T& have very different semantics.
> >
> > An optional T& has closer semantics to T* than a non-optional one.
>
> Didn't understand what you mean. Could you rephrase?

An optional<T&> has nearly the same semantics as a T*. I think the
only thing it's missing is pointer arithmetic, and it may be a little
more clear that optional<T&> is non-owning (though less clear that
it's Assignable). So I'm not sure either why anyone should use
optional<T&> instead of T*.

-- 
Namasté,
Jeffrey Yasskin