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From: Braddock Gaskill (braddock_at_[hidden])
Date: 2007-03-16 13:36:34

On Fri, 16 Mar 2007 13:32:05 -0400, Braddock Gaskill wrote:
> future<double> func1(const future<double> &a);
> future<double> func2(const future<double> &a);
> future<double> func3(const future<double> &a);

My pseudo-code typing was wrong here. I suppose it would be:
double func1(double a);
with f1.get() equiv to func1(f0.get()), etc

But you get the idea....

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