From: Marco (mrcekets_at_[hidden])
Date: 2007-04-19 19:00:57
On Thu, 19 Apr 2007 23:10:31 +0200, Michael Marcin
> I want to enable a function templated on a type T if a function it
> relies on overloaded on that type.
> template< typename T > inline
> typename detail::enable_if_overloaded< T (T), std::asin, radians<T>
> my_asin( T x )
> return radians<T>( std::asin( x ) );
I tried your code on gcc 4.1.1 and compiler crashes, too.
I found that if the function symbol passed as argument for Signature*
template parameter isn't overloaded, that is there is only one signature
bounded to the function name, your code works correctly.
IMO the problem is : if a function is overloaded what is its type ?
float std::asin(float )
long double std::asin(long double )
tipeof( std::asin ) is "float (float )" or "long double (long double )" ?
I don't know what the standard says about.
Anyway, I don't understand why vc and gcc crash.
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