Re: [boost] [lexical_cast] doc update

From: Alexander Nasonov (alnsn_at_[hidden])
Date: 2007-05-16 15:25:28

Phil Endecott wrote:
> ... 
> Q: What does lexical_cast<string> of an int8_t or uint8_t not do what I expect?
> A: As above, note that int8_t and uint8_t are actually chars and are 
> formatted as such.  To avoid this, cast to an integer type first:  lexical_cast<string>(static_cast<int>(n)).

Actually, you can write it a bit shorter: lexical_cast<string>(+n) ;-)

New revision is available at http://194.6.223.221/~nasonov/lexical_cast.htm

-- 
Alexander Nasonov
http://nasonov.blogspot.com
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