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From: David Abrahams (dave_at_[hidden])
Date: 2007-07-08 19:12:30


on Sun Jul 08 2007, "I Wei" <i.c.code-AT-gmail.com> wrote:

> With the boost::function<>::argN_type I can get boost::function's
> argument type. How can I do with the boost::lambda_functor?

You can't. Think about it by looking at the simplest lambda
expression:

   _1

What is the argument type? It could be anything.

-- 
Dave Abrahams
Boost Consulting
http://www.boost-consulting.com
The Astoria Seminar ==> http://www.astoriaseminar.com

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