Re: [boost] [fusion] value_of tranform_view

From: Tobias Schwinger (tschwinger_at_[hidden])
Date: 2007-07-13 05:38:18

Peter Dimov wrote:
> Stjepan Rajko wrote:
> 
>> [comes to a screeching halt from changing code]
> 
> Yep. :-)

Sorry for the false alarm!

>> I'm still not entirely on very sure footing when it comes to rvalues
>> and lvalues, so can I bother you with a practical clarification?
>>
>> So, if I have, say, a function object with operator()(int &), I should
>> specify result<F(int &)>, (but maybe if I have operator()(const int
>> &), or operator()(int), I can specify result<F(int)>?)
> 
> If you have operator()( int& ), you need result<F(int&)>. If you have 
> operator()( int ), you need both result<F(int)> and result<F(int&)> because 
> your operator() can take either an lvalue or an rvalue.

We'd also need 'int const &' (given we don't just provide 'result_type' 
or deduce whatever it is), right?

Regards,
Tobias