Boost logo

Boost :

From: Steve Kettle (skettle2000_at_[hidden])
Date: 2007-08-14 18:14:26

I have a question about the memory pool allocation that boost implements. Suppose we do the following:
   std::vector<int, boost::pool_allocator<int> > v;
   for (int i = 0; i < 10; ++i)
And the std::vector<int> is implemented so that it starts out with
 reserved space of 1 and doubles space every time. So At the end of the above loop v will have size 10 and reserved size 16.
Does the boost allocator mean that there will memory arrays lieing
 around of size 1,2,4,8 that can be reused ?
Eg if you do this:
  std::vector<int, boost::pool_allocator<int> > v;
   for (int i = 0; i < 10; ++i)
  std::vector<int, boost::pool_allocator<int> > v2;
   for (int i = 0; i < 8; ++i)
There will be no system call needed to get more memory -
 v2 will just reuse the memory in the pool_allocator<int> ?

Take the Internet to Go: Yahoo!Go puts the Internet in your pocket: mail, news, photos & more.

Boost list run by bdawes at, gregod at, cpdaniel at, john at