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From: Steven Watanabe (steven_at_[hidden])
Date: 2007-10-01 12:19:38


Dean Michael Berris <mikhailberis <at>> writes:

> And since it's linear inheritance, the derived type (or at least the
> one in the end of the inheritance hierarchy) will inherit all these
> overloads to operator=() which will enable the compiler to choose at
> compile time which overload it's going to use depending on what's on
> the right hand side of the operator=().

As long as you put using base::operator=; in the
derived type

In Christ,
Steven Watanabe

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