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From: Marco (mrcekets_at_[hidden])
Date: 2007-10-07 08:11:13

On Sun, 07 Oct 2007 10:41:52 +0200, Marco Costalba <mcostalba_at_[hidden]>

> I would think to fix completely the problem reported by Joel we could
> write instead:
> boost::is_convertible<F, boost::function<T> >
> But for unknown reasons this fails! All types of function pointers match!
> Could someone please be so kind to enlight me?
> Thanks
> Marco

Because boost::function has a constructor whose behavior is like this:

template< typename Functor >
function (Functor const& f)

it skips only integral type through enable_if.

So, except integral, everything is convertible to boost::function even

In order to implement signature deduction I exploits a support utility
used in the implementation of boost::function and a lot of metaprogramming.
Give a glance to detail::function::get_function_tag in function_base.hpp,
in order to learn how to discern between different kind of functors.

Marco Cecchetti

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