Re: [boost] BOOST_LOCAL_FUNCTION

From: Steven Watanabe (steven_at_[hidden])
Date: 2007-12-03 16:45:10

AMDG

Alexander Nasonov <alnsn <at> yandex.ru> writes:

> 
> Steven Watanabe <steven <at> providere-consulting.com> writes:
> 
> > #define BOOST_LOCAL_FUNCTION_DECLARE_ARGS() \
> >      conditional_declare<sizeof(is_declared(local_function_bound_args)) == \
> >      sizeof(no)>::apply<0> local_function_bound_args
> 
> Does it work when a bound argument depends on a template parameter???
> 
> The syntax in this case is
> *template* conditional_declare<...>::apply<0> local_function_bound_args;
> 
> which doesn't compile when *apply* is not a template.

You are correct, it wouldn't work if conditional_declare<...>
is a dependent type. However, void* is sufficient so it
should be okay.

In Christ,
Steven Watanabe