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From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2008-02-20 10:31:36
AMDG
Korcan Hussein wrote:
> Sorry about the poor title, it is difficult for me to explain the
> problem without code so here is a really simple example of what i'm
> trying to achieve but fails to compile with Boost.Bind:
>
> #include <boost/bind.hpp>
>
> struct FunFn {
>
> typedef void result_type;
> template < typename Fun >
> void operator()(Fun fn) const {
> fn();
> }
>
> } const Fn;
>
> void g() { std::cout << "hello\n"; }
>
> int main() {
> using namespace boost;
>
> bind(Fn, bind(Fn, bind(Fn, bind(Fn, ... bind(Fn, g))();
>
> }
>
This creates a function object that executes:
Fn(Fn(Fn(g())))
Since the inner functions return void, of course it fails.
> I get type deduction errors, however i have found workaround using
> Boost.Function for the time being:
>
> #include <boost/function.hpp>
>
> ...
> boost::function< void () >
> fnN = bind(Fn, g),
> fnN-1 = bind(Fn, fnN),
> ...,
> fn1 = bind(Fn, fn2),
> fn = bind(Fn, fn1);
>
> bind(Fn, fn)();
>
In Christ,
Steven Watanabe
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