From: Peter Dimov (pdimov_at_[hidden])
Date: 2008-04-07 07:29:50
> shunsuke wrote:
>> Eric Niebler wrote:
>>> I think that's right so far. Now imagine a simple identity function
>>> object, that just returns its argument unmodified:
>>> struct identity
>>> template<typename Sig>
>>> struct result;
>>> template<typename This, typename Arg>
>>> struct result<This(Arg)>
>>> typedef Arg type;
>>> template<typename Arg>
>>> Arg const &operator()(Arg const &arg)
>>> return arg;
>>> // and a non-const overload, too
>> Let me clarify.
>> This identity implementation is simply wrong (if you pass an rvalue to
>> because of inconsistency between decltype and result_of.
Yes, it's wrong, result<> and operator() are out of sync.
result_of<identity(X&)>::type returns X&, whereas identity()(x), where x is
an lvalue of type X, returns X const&.
Arg& operator()( Arg& ) const;
Arg operator()( Arg const& ) const;
maybe? I still don't remember how these overloads are resolved for a const
lvalue. Either way, this seems the best we can do in C++03.
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