From: Anthony Williams (anthony_w.geo_at_[hidden])
Date: 2008-04-07 13:11:11
"Peter Dimov" <pdimov_at_[hidden]> writes:
> Anthony Williams:
>> "Peter Dimov" <pdimov_at_[hidden]> writes:
>>> Eric Niebler:
>>>> Can you write what the identity function object would look like in
>>> struct identity
>>> template<class A> A operator()( A && a ) const
>>> return std::forward<A>( a );
>>> I guess.
>> No. That will convert lvalues to rvalues.
> Try it.
I have, and it doesn't work. Besides, you can see in the signature: it returns
"A" by value.
You either need the overloads, or you need a trait class to correctly
determine whether to return A or A&.
-- Anthony Williams | Just Software Solutions Ltd Custom Software Development | http://www.justsoftwaresolutions.co.uk Registered in England, Company Number 5478976. Registered Office: 15 Carrallack Mews, St Just, Cornwall, TR19 7UL
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