Re: [boost] "joinable"

From: Stefan Seefeld (seefeld_at_[hidden])
Date: 2008-05-28 10:45:07

Anthony Williams wrote:
> Stefan Seefeld <seefeld_at_[hidden]> writes:
>
>   
>> Anthony Williams wrote:
>>     
>>> OK. t.joinable() /really/ means t represents a thread of
>>> execution.
>>>       
>> Out of curiosity: Why do you consider a detached thread not to be a 
>> "thread of execution" ?
>>     
>
> It is a thread of execution, it's just that no thread object can
> represent a detached thread.
>   

thread t(task);
t.detach();
assert(t.joinable() == false);

t is now not joinable any more. But I find it confusing that "t does not 
refer to a thread of execution", even though I understand that this is 
not because the thread of execution has ceased to exist, but because t 
has been reset not to refer to it any longer.

> Yes, I did worry about that. Any more ideas?
>   

I still think 'joinable()' is the best name (so far).

       Stefan

-- 
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