Re: [boost] [extension] factory_map::get() suggestion

From: Jeremy Pack (rostovpack_at_[hidden])
Date: 2008-07-03 20:36:22

Steven,

Yeah, it isn't quite that simple. I read the original post too quickly and
thought he was referring to a different function.

I originally had a type for that std::map<int, factory<word> >, so it would
be something like type_factory_map<int, word>, which isn't much terser.
(thus, I removed it)

I think the best solution here is to make your own typedefs for your
specific case.

There are a couple of other places in the library though where I intend to
add the type of typedefs suggested.

Jeremy

On Thu, Jul 3, 2008 at 5:26 PM, Steven Watanabe <watanabesj_at_[hidden]>
wrote:

> AMDG
>
> Jeremy Pack wrote:
>
>> Yep! Good idea. I'll take care of it.
>>
>>
>>> For example, right now I have to do this:
>>>
>>> factory_map fm;
>>> std::map<int, factory<word> > & factory_list = fm.get<word, int>();
>>>
>>> It would be ideal to do this instead:
>>>
>>> factory_map fm;
>>> factory_map::type& factory_list = fm.get<word, int>();
>>>
>>>
>>
> Is it really that easy?  Doesn't the result of get
> depend on the particular template arguments?
> I don't quite see how you can get away with a
> single typedef.
>
> In Christ,
> Steven Watanabe
>
>
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