[boost] [lambda] Composing lambda expressions

From: Robert Jones (robertgbjones_at_[hidden])
Date: 2008-07-17 03:39:02

Given a bit of code like this,

struct S
{
  bool pred( ) const;
};

typdef vector<pair<string, S *> > V;
V :: const_iterator i;

i -> second -> pred( );

I'd like to rewrite the last line as a lambda expression. Looking at the
documentation, I think this is done with

bind( & S :: pred, bind( & V :: value_type :: second, _1 ) )( * i );

which works. But I'd rather be writing something like

( _1 -> second -> pred )( * i );

Am I right in thinking that Boost.Lambda just doesn't work like this, and
the frst form is how it's done?

Thanks, Rob.