Re: [boost] variant invariant

From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2008-08-04 18:56:12

AMDG

Emil Dotchevski wrote:
> Look, if I have:
>
> variant<foo,int> a=foo(....);
> variant<foo,int> b=foo(....);
>
> It is my understanding that if I now do:
>
> a=b;
>
> I may end up with an int in a. Do you think that this behavior is reasonable?
>   

You won't just end up with an int in a.
You will also end up with an exception.
Yes.  I think this behavior is reasonable.

In Christ,
Steven Watanabe