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From: Emil Dotchevski (emil_at_[hidden])
Date: 2008-08-04 20:43:17

On Mon, Aug 4, 2008 at 4:35 PM, Steven Watanabe <watanabesj_at_[hidden]> wrote:
> It does call operator= when both operands have the same type. Thanks.

Is it then true that even foo::operator= throws, in the code below:

variant<foo,int> a=foo(....);
variant<foo,int> b=foo(....);

we will never end up with an int in a? If that's the case, then maybe
I missed something in the documentation.

Emil Dotchevski
Reverge Studios, Inc.

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